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IntégralesCalculer l'intégrale suivante :\[ \int_{0}^{\pi} \sin(x) \, dx \]
\[\int_{0}^{\pi} \sin(x) \, dx = \left[ -\cos(x) \right]_0^{\pi} = -\cos(\pi) + \cos(0) = 1 + 1 = 2\]
