\( A = 3\left(1 + \frac{1}{3} - \frac{3}{2}\right) + \left(2 - \frac{1}{3}\right)\left(2 - \frac{3}{2}\right) \)
\( 1 + \frac{1}{3} - \frac{3}{2} = \frac{6 + 2 - 9}{6} = -\frac{1}{6} \)
\( 3 \times (-\frac{1}{6}) = -\frac{1}{2} \)
\( 2 - \frac{1}{3} = \frac{5}{3} \), \( 2 - \frac{3}{2} = \frac{1}{2} \)
\( \frac{5}{3} \times \frac{1}{2} = \frac{5}{6} \)
\( A = -\frac{1}{2} + \frac{5}{6} = \frac{-3 + 5}{6} = \frac{2}{6} = \frac{1}{3} \)
\( C = \sqrt{96} + 2\sqrt{6} - 2\sqrt{24} - 3\sqrt{54} \)
\( \sqrt{96} = \sqrt{16 \times 6} = 4\sqrt{6} \)
\( 2\sqrt{24} = 2\sqrt{4 \times 6} = 4\sqrt{6} \)
\( 3\sqrt{54} = 3\sqrt{9 \times 6} = 9\sqrt{6} \)
\( C = 4\sqrt{6} + 2\sqrt{6} - 4\sqrt{6} - 9\sqrt{6} = (4+2-4-9)\sqrt{6} = -7\sqrt{6} \)
\( D = \frac{1}{3}\sqrt{363} + \sqrt{108} - \sqrt{300} + \frac{2}{\sqrt{12}} - 2\sqrt{\frac{75}{36}} \)
\( \sqrt{363} = \sqrt{121 \times 3} = 11\sqrt{3} \) → \( \frac{1}{3} \times 11\sqrt{3} = \frac{11}{3}\sqrt{3} \)
\( \sqrt{108} = \sqrt{36 \times 3} = 6\sqrt{3} \)
\( \sqrt{300} = \sqrt{100 \times 3} = 10\sqrt{3} \)
\( \frac{2}{\sqrt{12}} = \frac{2}{2\sqrt{3}} = \frac{1}{\sqrt{3}} = \frac{\sqrt{3}}{3} \)
\( 2\sqrt{\frac{75}{36}} = 2 \times \frac{\sqrt{75}}{6} = \frac{\sqrt{75}}{3} = \frac{5\sqrt{3}}{3} \)
\( D = \frac{11}{3}\sqrt{3} + 6\sqrt{3} - 10\sqrt{3} + \frac{\sqrt{3}}{3} - \frac{5\sqrt{3}}{3} \)
\( D = \left(\frac{11}{3} + 6 - 10 + \frac{1}{3} - \frac{5}{3}\right)\sqrt{3} = \left(\frac{11 + 1 - 5}{3} - 4\right)\sqrt{3} = \left(\frac{7}{3} - 4\right)\sqrt{3} = -\frac{5}{3}\sqrt{3} \)